помогите! (х+1)*(х+2)*(х+4)*(х+5)=40
x=0
1*2*4*5=40
(x^2 + 6x + 5) * (x^2 + 6x + 8) = 40
x^2 + 6x + 5 = t
t * (t + 3) = 40
t^2 + 3t -40 = 0
t1 = -8 t2 = 5
x^2 + 6x + 5 = -8 x^2 + 6x + 5 = 5
x^2 + 6x + 13 = 0 x^2 + 6x = 0
нет корней х = 0 х = -6
Ответ: -6; 0