mCuSo4-16г + KOH
mKoh-?
Ню и N KOH — ?
CuSO4 +2KOH---> Cu(OH)2 + H2O
n(CuSO4)= m /M=16/160= 0.1 моль
2n(CuSO4)= n (KOH)
n(KOH)=0.2 моль
N(KOH) =n x Na= 0.2 x 6.02* 10(23)= 1.2*10(23)