Fe +2HCl=FeCL2 +H2
n(H2)= 2.24/22.4=0.1 моль
n(H2)=n(Fe)
m(Fe)= n x M=0.1 x 56=5.6г
w(Fe)= 5.6/6= 0.933 или 93.3 %
2n(Fe)=n(HCL)
n(HCL)= 0.2 моль
m(HCL)= nx M=0.2 x36.5= 7.3г
V(HCL)= m x 100/ p x%=7.3 x 100/18.25x 1.09= 36.7мл